If ABCDE is a regular pentagon and MNCD is a square (with M and N inside
ABCDE), compute the value of m∠AMN − m∠EAM in degrees.
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∠ABN=90
o
∠ABC=108
o
∠MBC=360
o
−90
o
−108
o
=162
o
∠BMC+∠MBC+∠BCM=180
o
∠BMC+∠BCM=180
o
−162
o
=18
o
∠BMC=18
o
−∠BCM
But, ∠BCM=∠BMC
2∠BCM=18
o
∠BCM=9
o
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