If abcdef is a hexagon
Prove that AB+CD+EF=BC+DE+AF
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Explanation:
given:hexagon abcdef
to prove:ab+cd+ef=bc+de+af
proof:
am=ar (tangent from point A)
bm+bn
co+no
od+dp
eq+pe
qf+fr
add(1)(2)(3(4)(5)(6)
am+bm+co+od+eq+qf+=bn+no+dp+pe+qf+fr
ab+cd+ef=bc+de+af
hence proved
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