if ABCDEF is a regular hexagon find the angles of ∆ ABC
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we know that
asp of hexagon is
sum of all angles is 720
since it's a regular hexagon
each angle=720/2 =120
so angle b = 120
now in trABC
angle(A+B+C)=180. (asp of tri).
angle(A+120+C)=180
angle (A+C)=60
angle(A+A)=60. (side AB=BC)
angle A =30
thus
angle B =120
angle A=30
angle C=30
asp of hexagon is
sum of all angles is 720
since it's a regular hexagon
each angle=720/2 =120
so angle b = 120
now in trABC
angle(A+B+C)=180. (asp of tri).
angle(A+120+C)=180
angle (A+C)=60
angle(A+A)=60. (side AB=BC)
angle A =30
thus
angle B =120
angle A=30
angle C=30
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