if ABIIDE, angle ABC=115º and angle BCD=55°, then find the value of x pls give me elaborated answer
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Answered by
1
Answer:
120°
Step-by-step explanation:
Solving Method -
∠BCD = ∠ABC - (180 -∠CDE)
55 = 115 - (180 - x)
55 = 115 - 180 + x
55 = - 65 + x
55 + 65 = x
120 = x
x = ∠CDE = 120°
Chking Method -
∠BCD = ∠ABC - (180 - ∠CDE)
∠BCD = 115 - (180 - 120)
∠BCD = 115 - 60
∠BCD = 55
55 = 55
LHS = RHS
Hope it helps you mate..
:)
Answered by
5
Answer:
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Step-by-step explanation:
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