If absolute error is 1V and % error is 1.25% then Relative accuracy is_________
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Given :- ∂A = 1 , εA = 1.25%
To find :- relative accuracy
Solution :-
- here we have to find limits of value
- A = ∂A ÷ εA × 100
- A = 1 ÷ 1.25 × 100
- A = 80
- So original value is A= 80
- Limits of value = A ± ∂A
- = 80 ± 1
- = 79 , 81
So accuracy is 79 , 81
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