Math, asked by JOSHUA999123, 1 year ago

if AC=17 BC =8 THEN FIND AC^2=AB^2+BC^2

Answers

Answered by SumitDutonde22

Given;- AC = 17 , BC = 8
we have AC² = AB² + BC²
Therefore, ( 17 )² = AB² + ( 8 )²
Therefore, 289 = AB² + 64
Therefore, AB² = 289 - 64
Therefore, AB² =225
Taking square root,
Therefore, AB = 15

JOSHUA999123: when we take 289 to right side it becomes -289

SumitDutonde22: yes you are right

SumitDutonde22: but as you can see, we have exchanged both ( 289 ) and ( AB² ) and when we interchange two values of both R. H. S. and Ĺ. H. S, the value remains the same

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