if AC angle Ab and angle BECis equal to 110 then find the value of x and y
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Given:-AC=AB
angle BEC=110°
solution::--
As we know the rule
=>The sum of Opposite angle of a cyclic quadrilateral is equal to 180°
following this rule,
angleBDC+angle BEC=180
y+110=180
y=180-110
y=70°
In ∆ABC
AC=AB
forming isosceles triangle.
and by the rule
=>Angles in the same segment of. circle are equal.
angleBAC=angleBDC
angleBAC==70
angleABC=angleACB
angle opposite to equal side are equal.
so,
using angle sum property in ∆ABC
angleABC+angleACB+angleBAC=180
x+x+70=180
2x=180-70
2x=110
x=55
so,x=55
& y=70
@Altaf
angle BEC=110°
solution::--
As we know the rule
=>The sum of Opposite angle of a cyclic quadrilateral is equal to 180°
following this rule,
angleBDC+angle BEC=180
y+110=180
y=180-110
y=70°
In ∆ABC
AC=AB
forming isosceles triangle.
and by the rule
=>Angles in the same segment of. circle are equal.
angleBAC=angleBDC
angleBAC==70
angleABC=angleACB
angle opposite to equal side are equal.
so,
using angle sum property in ∆ABC
angleABC+angleACB+angleBAC=180
x+x+70=180
2x=180-70
2x=110
x=55
so,x=55
& y=70
@Altaf
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0
Answer:
answer is 35................
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