Math, asked by kumudsrivastava008, 7 months ago

if AC=BD in a parallelogram ABCD then angle A = 2 angle B​

Answers

Answered by Anonymous
3

Step-by-step explanation:

ANSWER

ABCD is a parallelogram.

Therefore,

AD∥BC

⇒∠ACB=∠DAC=30°

Now, ∠AOB is an exterior angle of △BOC.

As we know that exterior angle is equal to the sum of two interior opposite interior angles.

Therefore,

∠OBC+∠OCB=∠AOB

⇒∠OBC+30°=72°

⇒∠OBC=72°−30°=42°

∴∠DBC=∠OBC=42°

Hence ∠DBC is 42°.

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