if AC=BD in a parallelogram ABCD then angle A = 2 angle B
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Step-by-step explanation:
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ABCD is a parallelogram.
Therefore,
AD∥BC
⇒∠ACB=∠DAC=30°
Now, ∠AOB is an exterior angle of △BOC.
As we know that exterior angle is equal to the sum of two interior opposite interior angles.
Therefore,
∠OBC+∠OCB=∠AOB
⇒∠OBC+30°=72°
⇒∠OBC=72°−30°=42°
∴∠DBC=∠OBC=42°
Hence ∠DBC is 42°.
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