Math, asked by HaqqiAdeeba3281, 1 year ago

If AC:BD is 3:4 find area of rhombus ABCD having one side a

Answers

Answered by Khushi0511
6
Since, area of a rhombus is =)half the product of their diagonals. or [d1×d2/2]

let diagonal AC= 3a and diagonal BD= 4a

area of rhombus = (3a × 4a)/2 = 6a2

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Answered by Swarup1998
3
The answer is given below :

The ratio of the diagonals is 3 : 4

Let, a be the common multiple.

Then the diagonals are represented as 3a units and 4a units.

Area of the rhombus ABCD

= 1/2 × product of their diagonals

= 1/2 × (3a × 4a) unit²

= 6a² unit²

Thank you for your question.
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