If AC:BD is 3:4 find area of rhombus ABCD having one side a
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Since, area of a rhombus is =)half the product of their diagonals. or [d1×d2/2]
let diagonal AC= 3a and diagonal BD= 4a
area of rhombus = (3a × 4a)/2 = 6a2
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let diagonal AC= 3a and diagonal BD= 4a
area of rhombus = (3a × 4a)/2 = 6a2
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Answered by
3
The answer is given below :
The ratio of the diagonals is 3 : 4
Let, a be the common multiple.
Then the diagonals are represented as 3a units and 4a units.
Area of the rhombus ABCD
= 1/2 × product of their diagonals
= 1/2 × (3a × 4a) unit²
= 6a² unit²
Thank you for your question.
The ratio of the diagonals is 3 : 4
Let, a be the common multiple.
Then the diagonals are represented as 3a units and 4a units.
Area of the rhombus ABCD
= 1/2 × product of their diagonals
= 1/2 × (3a × 4a) unit²
= 6a² unit²
Thank you for your question.
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