if AC =BD prove AB=CD
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Answer:
Here, we use
axiom 3 which states that equals are subtracted from equals then the remainders are also equal.
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Solution:
Given, AC = BD......(1)
From the figure,
AC = AB + BC
&
BD = BC + CD
On putting these values in eq 1,
⇒ AB +
BC = BC + CD
According to Euclid’s axiom, when equals are
subtracted from equals, remainders are also equal.
On Subtracting BC from both sides,
AB + BC – BC = BC + CD – BC
AB = CD [ by axiom 3 of Euclid]
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Hope this will help you....
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