Question

if AC>AB and AD is the bisector of ∠A,show that ∠ADC>∠ADB.

Answer 1

ΔABC

AC > AB

and AD is the bisector of ∠A

⇒ ∠BAD = ∠CAD =

Also In ΔABD

∠ABD + ∠BAD + ∠ADB = 180°

⇒ ∠ADB = 180° –

In ΔADC

∠ACD + ∠CAD + ∠ADC = 180°

⇒ ∠ADC = 180° –

Now

∠ABD > ∠ACD  (angle opposite to longer side is greater)

Answer 2

Hy mate____________________
___________________


◀ Here is your solution ▶
______________________

✔️Given: AC>AB and AD is bisector of
angle A

➡ angleBAD = angle
CAD = Angle A/2

  Also in triangle ABDangle
______________________
➡ ABD+ angleBAD + angle
➡ ADB = 180 degree.

➡ angle ADB
= 180-angle ABD + Angle A/2

➡️➡️➡️ Now➡️➡️➡️

angle ABD> angle ACD ...(∵ angle opposite to longer side is greater)

➡ angle ABD +angle A/2 > angle ACD + angle A/2

➡ 180-angle ACD + angle A/2 > 180-angle ABD +angle A/2.

➡ angle ADC > angle ADB
_________________________

Thankyou✌✌✌
Brainly user...➡️➡️➡️➡️