If ACB and n(A) = 18
n(B)=40,then
n(ANB) is
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Given : n(A ∩ B) = 18 , n(A) = 18 , n(B) = 40
To Find : n( A ∪ B)
Solution:
n( A ∪ B) = n(A) + n(B) - n(A ∩ B)
n(A) = 18
, n(B) = 40
n(A ∩ B) = 18
=> n( A ∪ B) = 18 + 40 - 18
=> n( A ∪ B) = 40
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