Question

IF acb is any three digit number, then find the divisibility of acb+bac+cba.​

Answer 1

Step-by-step explanation:

acb = 100a+10c+b

bac= 100b+10a+c

cba= 100c+10b+a

on adding all eq

acb+bac+cba=100a+10c+b+100b+10a+c+100c+10b+a

acb+bac+cba= 111a+111b+111c

acb+bac+cba = 111(a+b+c)

hence it is divisible by 111

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