if acceleration (a) =5m/s^2,distance (s) =8.4m , final velocity (v) = 10, find initial velocity (u) =?
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Answered by
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We know that v^2=u^2+2as
10×10=u^2+2×5×8.4
100=u^2+84
100-84=u^2
16=u^2
√16=u
4m/s=u
Hence initial velocity is 4m/s.
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