Question

If acceleration (A), velocity (V) and mass (M) are taken as fundamental quantities then dimensional formula of length is

Answer 1

A=LT^-2

V=LT^-1

M=M^1

[LT^-2]^x [LT^-1]^y [M]^z= L^1

L^x+y M^z T^-2x-y = L^1

So,

x=-1

y=2

z=0

Dimensions of Length is=

V^2/A