Question

If acceleration due to gravity at distance d[< R]
from the centre of earth is ß, then its value at
distance d above the surface of earth will be [where
Ris radius of earth]​

Answer 1

at the center of the earth die to gravitational force/energy

Answer 2

The acceleration of gravity decreases as we do below or above the earth's surface.

Explanation:

The acceleration of gravity is maximum at the surface of earth.

We know the force of attraction between two objects.

                                     ⇒ F = $\frac{GMm}{R^{2} }$

where, R is the radius of earth.

M is the mass of earth.

m is the mass of the object.

G is the gravitational constant.

If the object is above the earth,

                            ⇒   ß = $\frac{GMm}{(d + R)^{2} }$

Here, d is the distance between the planet and object

And if the object is below the surface,

                                      ⇒   ß = $\frac{GMm}{d^{2} }$