if acceleration due to gravity on the surface of the Earth is 9.8 M per second square its value at a height of 6400 km is what? And radius of the earth is equal to 6400 km
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Answer:100 2
Explanation:
https://app.edmentum.com/mimetex/mimetex?\fs3%20\textrm{T}_{(^{\circ}\textrm{C})}=%20\left%20(%20\textrm{T}_{(^{\circ}\textrm{F})}-32%20\right%20)\times%20\frac{5}{9}
hope this help
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