Question

if acceleration of a particle at any time is given by a=2t+5 calculate the velocity after 5s if starts from rest​

Answer 1

Explanation:

a=2t+5

dv/dt=2t+5

then integreate

v=2t^2/2+5

in 5sec

v=25+5=30

Answer 2

Answer:

Given:

Acceleration (a): 2t + 5

As it starts from rest, initial velocity (u) = 0 m/s

To find:

Velocity (v) = ?

Solution:

As acceleration is rate of change of velocity per unit time.

Therefore,

Acceleration (a) =

$\frac{velocity \: (v) \: - \: initial \: velociy\: (u)}{time \: (t)}$

Thus,

$2(5)+ 5 = \frac{v \: - \: 0}{5} \\ 10 + 5 = \: \frac{v - 0}{5} \\ 15 \times 5 = v \\ therefore \\ v \: = 75 \: ms^{ - 2}$

Therefore,

Velocity is 75m/s.

Hope it helps you

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