Question

If acceleration of particle is given by a = 3 t2 , find velocity of particle at t = 3 seconds, if initially particle was at rest.

Answer 1

Explanation:

a=t2−3t2+5

v=∫adt+c1=4t4−33t3+5t+C1

At t=1s,v=6.25ms−1

6.25=414−13+5×1+C1⇒C1=2

⇒v=4t4−t3+5t+2

x=∫vdt+C2=20t5−414+25(1)2+×1+C2⇒C2=