If ∠ACD = 114º and ∠ABC = 1/2 ∠BAC What is the value of ∠ABC ?
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Solution :-
Let us assume that, ∠BAC is equal to 2x .
So,
→ ∠ABC = (1/2)∠BAC
→ ∠ABC = (1/2) * 2x
→ ∠ABC = x
also, given that,
→ ∠ACD = 114°
then,
→ ∠ABC + ∠BAC = ∠ACD { Exterior angle is equal to sum of opposite interior angles }
→ x + 2x = 114°
→ 3x = 114°
→ x = 38° (Ans.)
Hence, the value of ∠ABC is equ to 38° .
Learn more :-
In the figure along side, BP and CP are the angular bisectors of the exterior angles BCD and CBE of triangle ABC. Prove ∠BOC = 90° - (1/2)∠A .
https://brainly.in/question/32333207
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