If acostheta + bsintheta = m and asintheta - bcostheta = n then asq. + bsq.= ?
A) m + n
B) msq. - nsq.
C) msq. + nsq.
D) none of these
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Answer :
Given that,
a cosθ + b sinθ = m ...(i)
a sinθ - b cosθ = n ...(ii)
Now, squaring and adding (i) and (ii), we get
(a cosθ + b sinθ)² + (a sinθ - b cosθ)²
= m² + n²
⇒ (a² cos²θ + 2 ab cosθ sinθ + b² sin²θ)
+ (a² sin²θ - 2 ab sinθ cosθ + b² cos²θ)
= m² + n²
⇒ (a² + b²) (cos²θ + sin²θ) = m² + n²
⇒ a² + b² = m² + n²
Thus, option (c) is correct.
#MarkAsBrainliest
Given that,
a cosθ + b sinθ = m ...(i)
a sinθ - b cosθ = n ...(ii)
Now, squaring and adding (i) and (ii), we get
(a cosθ + b sinθ)² + (a sinθ - b cosθ)²
= m² + n²
⇒ (a² cos²θ + 2 ab cosθ sinθ + b² sin²θ)
+ (a² sin²θ - 2 ab sinθ cosθ + b² cos²θ)
= m² + n²
⇒ (a² + b²) (cos²θ + sin²θ) = m² + n²
⇒ a² + b² = m² + n²
Thus, option (c) is correct.
#MarkAsBrainliest
rajpardhi423:
Thank u very much. It really helped me a lot
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