If AD = 14cm; then find the perimeter of ABC
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Answer:
AD=AE =14cm
AD =AC + BD
AE = AC+CE
BC = FB +FC
BF = BD [TANGENTS FROM A SINGLE POINT]
CE =CF [TANGENTS FROM A SINGLE POINT]
AD = AB +BF ----1
AE = AC +CF ---2
AD + AE = AB +FB+AC+CF
AD + AE = AB + AC + BC =PERIMETER OF TRIANGLE ABC
28 IS THE PERIETER OF TRIANGLE.
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