Question

If AD = AE and DB = EC , then
prove that ∆AEB =~ ∆ADC

PLZ GIVE ACCURATE ANSWER WITH EXPLANATION ​

Answer 1

Step-by-step explanation:

We have AE=AD and CE=BD.

Adding, we get AE+CE=AD+BD

⇒AC=AB.

In triangles AEB and ADC, we have

AE=AD ... (given);

AB=AC .... (proved);

∠EAB=∠DAC, (common angle).

By SAS postulate △AEB≅△ADC.

Answer 2

Answer:

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