Question

If ad ae bc are tangents to a circle at d e f respectively then

Answer 1

AD=AE, CD=CF, AND BE=BF

now, 2AD= AD+ AD=AD+AE

=(AC+CD)+(AB+BE)

2AD=AC+AB+(CD+BE)

2AD=AC+AB+(CF+BF)

2AD=AC+AB+BC

Answer 2

Answer:

See the future above

Hopefully helpful

Vote as brainliest