Math, asked by Anonymous, 10 months ago

if AD and BD are bisector of angle CAB and angle CBA, respectively find the sum of angles x and y ​

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Answers

Answered by harinni92
13

Answer:

Step-by-step explanation:

The picture in the attached figure

Step 1

we know that

It is given that AD and BD are bisectors of ∠CAB and ∠CBA respectively.

Therefore,

x = ∠CAB/2 -----> equation 1

y = ∠CBA/2 -----> equation 2

Step 2

In triangle ABC,

∠CAB + ∠CBA + ∠ACB = 180° ----> [The sum of all three angles of a triangle is 180°]

∠CAB + ∠CBA + 110° = 180°

∠CAB + ∠CBA = 180° - 110°

∠CAB + ∠CBA = 70° ------> divide by 2 both sides

∠CAB/2 + ∠CBA/2 = 70/2 -------> equation 3

substitute equation 1 and equation 2 in equation 3

x+y=35

Hence,

the answer is

x+y =35°

⇒ x + y = 35° ...[From equation (1) and (2)]

HOPE IT HELPS

Answered by hukam0685
2

The sum of angles;

\bf \red{ \angle \: x + \angle \: y = {40}^{ \circ}}  \\

Step-by-step explanation:

Given:

  • A triangle ABC.
  • \angle \: ACB =  {100}^{ \circ}  \\
  • AD and BD are the angle bisector of \angle \: CAB and \angle \: CBA respectively.

To find:

  • Find the sum of angles x and y.

Solution:

Theorem to be used:

Angle sum property of triangle:

  • The sum of interior angles of triangle is 180°.

Step 1:

Find the sum of angles; i.e.\angle \: CAB and \angle \: CBA.

According to angle sum property of triangle.

\angle \: CAB + \angle \: CBA + \angle \: ACB=  {180}^{ \circ}  \\

or

\angle \: CAB + \angle \: CBA +  {100}^{ \circ}=  {180}^{ \circ}  \\

or

\bf \angle \: CAB + \angle \: CBA  =  {80}^{ \circ}...eq1  \\

Step 2:

Find the sum of angles x and y.

As AD and BD are angle bisectors.

So,

2x = \angle \: CAB \\

and

2y = \angle \: CBA\\

put these values in eq1

2x + 2y =   {80}^{ \circ}  \\

or

\bf x + y =   {40}^{ \circ}  \\

Thus,

Sum of angle x and angle y is 40°.

\bf \angle \: x + \angle \: y = {40}^{ \circ}  \\

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