If Ad || Bc,find the value of x in the figure
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here ad||BC
and angle B =60°
angle DAC=70°
since AD||BC=angle DAC=ACB(alternate interior angles)
so Acb=70°
in ∆abc,
60°+70°+x=180°{asp)
130°+x=180
x=50°
and angle B =60°
angle DAC=70°
since AD||BC=angle DAC=ACB(alternate interior angles)
so Acb=70°
in ∆abc,
60°+70°+x=180°{asp)
130°+x=180
x=50°
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