Question

If AD, BE and CF are medians of AABC, prove that
3(AB²+ BC²+ CA²) = 4(AD² + BE² + CF²).​

Answer 1

Assuming vector notion .

AD=D-A ,BE=B-E ,CF = F-E

D=(B+C )/and so on

AD+BE+CF=D+E+F-(A+B+C)

=(B+C)/2+(A+C)/2+(A+B)/2-(A+B+C)=0

And I think i hope u understand my friend