Question

if AD is a median of triangle ABC, the the value of (AB+AC) /AD can't be equal to​
4
5/2
3/2
3

Answer 1

Answer:We have,

InΔABC,AB=AC.and AD is the median.

Then prove that,

InΔABC,AD is the perpendicular bisector of BC.

Proof:-

In

ΔADBandΔADC

AB=AC(Giventhat)

AD=AD(Commonline)

∠ADB=∠ADC(Everyrightangle)

Then, ΔADB≅ΔADC by S.A.S. rule

So, AD is the perpendicular bisector of BC.

Hence proved.

Answer 2

Step-by-step explanation:

InΔABC,AB=AC.and AD is the median.

Then prove that,

InΔABC,AD is the perpendicular bisector of BC.

Proof:-

In

ΔADBandΔADC

AB=AC(Giventhat)

AD=AD(Commonline)

∠ADB=∠ADC(Everyrightangle)

Then, ΔADB≅ΔADC by S.A.S. rule

So, AD is the perpendicular bisector of BC.

Hence proved.

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