Question

If AD is an altitude of an isosceles triangle ABC in which AB = AC and D lies on BC, then​

Answer 1

Answer:

please complete the full question

Step-by-step explanation:

D lies on BC, then

D is perpendicular to BC

it is an isosceles triangle ABC in which AB = AC

Answer 2

Step-by-step explanation:

Given,

△ABC is an isosceles triangle,

⇒AB=AC

⇒AD is the altitude

∴∠ADC=∠ADB=90

∘

To prove,

AD bisects BC

Proof,

In △ADB and △ADC

∠ADC=∠ADB=90

∘

AB=AC [GIVEN]

AD=AD [COMMON SIDE]

∴△ADB≅△ADC [by SAS congruence]

by CPCT,BD=DC

Hence AD bisects BC