Question

if ad is an median of triangle abc then the value of ad/ab-ac can be equale to

Answer 1

Answer:

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Answer 2

$\frac{AD}{AB-AC}$ > 0

Given,

In the △ABC, AD is the median of triangle, and it is on the side BC

Now, In △ABD,

AB+BD>AD (Sum of two sides of triangle is greater than the third side)

Now, In △ACD,

AC+CD>AD (Sum of two sides of triangle is greater than the third side)

Hence, the value of AD/AB-AC will be positive i.e., greater than 0.