if AD is perpendicular to BC
prove that AB square + CD square = BD square + AC square
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Since triangles ABD and ACD are right-angled triangles at D.
∴ AD
2
=AD
2
+BD
2
.....(i)
and, AC
2
=AD
2
+CD
2
.....(ii)
Subtracting (ii) from (i), we get
AB
2
−AC
2
=BD
2
−CD
2
⇒ AB
2
+CD
2
=AC
2
+BD
2
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