If AD is the angle bisector of A of an isosceles triangle ABC, then prove that BD = DC.
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Step-by-step explanation:
In Δ ABD and Δ ACD,
∠BAD=∠CAD (given)
AD=AD (common)
AB=AC (two sides of an isosceles triangle are equal)
∴ΔABD ≅ ΔACD (By SAS congruence rule)
∴BD=CD (By CPCT)
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