Question

If AD is the median of A ABC, whose vertices are A(-2, 6), B(2, 1) and C(8, 7), then the length of median AD is




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Answer 1

Answer:

Since , median of a ∆ meets the side at is mid point

Mid point of BC = ( (x1 + X2 )/2 , (y1 + y2 )/2 ) =( (2+8)/2 , ( 7+1) /2 )= (5,4)

Therefore pt. D = (5,4)

Using distance formula ,

AD = √((X2 - x1 )² + (y2 - y2)² )

= √(-2-5)² + (4-6)² = √ ( 49 + 4 ) = √53 units ( Ans. )