Question

if AD is the median of an isosceles triangle ABC and angle A =120degree and AB=AC then find the value of angle ADB

Answer 1

the base at which the median ends is always 90°. so if D is the point then ∠D is 90°.

so the answer of ∠ADB = 90°

Answer 2

Answer:

Angle ADB =90°

Step-by-step explanation:

ADB is a right angle beacuse AD is the median of triangle ABC and the point where the median ends always make an right angle , so angle ADB is a right angle = 90°

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