if Aditya travels to school from his home at the speed of 3km/hr,then he reaches school 5min late.At the speed of 4km/hr he reaches school 5min early. Find the distance between his home and school.
Answers
distance between school and home is 2km
let distance between school and home is x km and right time taken to reach the destination is t hrs.
case 1: speed = 3 km/hr , time = t + 5min = t + 5/60 hr = (t + 1/12) hrs
so, x = 3km/h × (t + 1/12)hr
⇒x = 3(t + 1/12) ......(1)
case 2 : speed = 4km/h, time = (t - 5 min)
= (t - 5/60) = (t - 1/12) hrs
so, x = 4(t - 1/12) .........(2)
from equations (1) and (2),
3t + 3/12 = 4t - 4/12
⇒t = 7/12
putting in equation (1),
x = 3(7/12 + 1/12)
= 3 × 8/12 = 3 × 2/3 = 2 km
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Answer:
the answer is above in the photo
