Question

If Aditya walks to school from his home at a speed of 3 km/hr, then he reaches school 5 minutes late. At a speed of 4km/hr he reaches school 5 minutes early . Find the distance between his home and school.​

Answer 1

Answer:

2 km

Step-by-step explanation:

d is distance to school

t is time it takes to get there if he’s ontime.

3(t+5) =d

4(t-5)=d

given from the problem statement,

3(t+5)=4(t-5)

3t+15=4t-20

15+20=4t-3t

t=35 minutes

d=2km

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