If adjacent angles of a rhombus are in ratio 3:2 . Find all the other three angles .
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Answered by
2
Hi Mate!!!
Let the adjacent angles of rhombus are in ratio 3x : 2x
=>. 3x + 2x + 3x + 2x = 360
=>. x = 36°
So, the angles are
3 ( 36° ) , 2 ( 36° ) , 3 ( 36 ° ) and 2 ( 36° )
Have a nice time..
Let the adjacent angles of rhombus are in ratio 3x : 2x
=>. 3x + 2x + 3x + 2x = 360
=>. x = 36°
So, the angles are
3 ( 36° ) , 2 ( 36° ) , 3 ( 36 ° ) and 2 ( 36° )
Have a nice time..
Answered by
16
Answer :
Given adjacent angles of rhombus are in ratio 3 : 2
Let these two angles be 3x and 2x
Now as we know that -
Sum of the adjacent angles of rhombus is 180°
Therefore -
3x + 2x = 180°
5x = 180°
x = 180 ÷ 5 = 36°
now x = 36°,
therefore two adjacent angles are
3(x) = 3(36) = 108°
2(x) = 2(36) = 72°
Now, we need to find other two angles.
Let one of those angles be p
then,
72° + p = 180° (adjacent angles)
p = 180° - 72°
p = 108°
let the other angle be z
then,
z + 108° = 180°
z = 180° - 108°
z = 72°
Therefore all 4 angles are 108°,72°,108° and 72°
Given adjacent angles of rhombus are in ratio 3 : 2
Let these two angles be 3x and 2x
Now as we know that -
Sum of the adjacent angles of rhombus is 180°
Therefore -
3x + 2x = 180°
5x = 180°
x = 180 ÷ 5 = 36°
now x = 36°,
therefore two adjacent angles are
3(x) = 3(36) = 108°
2(x) = 2(36) = 72°
Now, we need to find other two angles.
Let one of those angles be p
then,
72° + p = 180° (adjacent angles)
p = 180° - 72°
p = 108°
let the other angle be z
then,
z + 108° = 180°
z = 180° - 108°
z = 72°
Therefore all 4 angles are 108°,72°,108° and 72°
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