Question

if adjacent side is 4cm ,opposite side is 9cm,find hypotonus of triangle​

Answer 1

hypotenuse=v9^2+4^2 =v81 +16=

=v97=9.8cm

Answer 2

$(hypotunuese) {}^{2} = ( {adj})^{2} + ( {opp})^{2}$

$hyp = \sqrt{ {4 }^{2} + {9}^{2} }$

$hyp = \sqrt{16 + 81}$

$hyp = \sqrt{97}$