Math, asked by karanthanvi2006, 1 month ago


If ages of Mohan, Sohan and Rohan are in the ratio 2:3:4pes of Sehat
are in the ratio 3:4:3 and if present age of Mohan is 12 years, the
?​

Answers

Answered by chughchitrakshi
0

Answer:

let ages be 2x, 3x, 4x

and 2x= 12

x= 6

so 3x = 3×6 = 18(Sohan age)

4x = 4×6 = 24(Rohan age)

Step-by-step explanation:

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Answered by Devkumarr
0

Answer:

18 and 24 is the present age of Rohan and Sohan.

Step-by-step explanation:

AS THE QUESTION IS NOT PROPER, BY CONSIDERING WE HAVE TO FIND THE AGES OF ROHAN AND SOHAN

  • In context to the question we have to fin the present ages of Rohan and Sohan .

Given;

Ratios of their ages = 2:3:4

let "x" be the years

then,

Age of Mohan = 2x

Age of Rohan = 3x

Age of Sohan = 4x

present age of Mohan is given 12

therefore,

2x = 12

x = 6

BY putting the value of x in ages of Rohan and Sohan , we get,

Age of Rohan = 3x = 3(6) = 18 years

Age of Sohan = 4x = 4(6) = 24years

18 and 24 is the present age of Rohan and Sohan.

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