If Ahmad lends Rs. 8000 for 9 months, Muneeb lends Rs. 10000 for 12 months and total
interest paid is Rs. 1200, how much should each receive?
Answers
Answered by
1
- 8000x9÷10000×12
- 72÷120
- 3/5
- 3+5=8
- 1200x3/8=450
- 1200×5/8=750
Answered by
1
Step-by-step explanation:
given , Ahmed
p=8000
time=9months =3/4 years
Muneeb,
p=10000
time=12months=1years
putting together
some of interest of Ahmed and Muneeb
we all know that formule,
- SI=p*r*t/100
- some if interest of ahmed +muneeb
- p*r*t/100 + p*r*t/100 =Rs.1200
- 8000*r*3/4/100 + 10000*r*1/100=1200
- r*60 + r*100 =1200
- 60r+100r=1200
- 160r=1200
- r=15/2
- for ahmed+ahmed
- p*r*t/100 +p*r*t/100
- 15/2(8000*3/4/100 + 10000*1/100)=1200
- 1200=1200
- so,ahmed lend interest=3/4 of 1200=900,1200-900=300
- ahmed left one 1200-300=900
- gets 300 as interset and muneeb gets900
- as interest
- ahmed amount=8000+300=8300
- Muneeb amount=10000+900=10900
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