Math, asked by hadzch009, 2 months ago

If Ahmad lends Rs. 8000 for 9 months, Muneeb lends Rs. 10000 for 12 months and total
interest paid is Rs. 1200, how much should each receive?

Answers

Answered by skverma807
1
  1. 8000x9÷10000×12
  2. 72÷120
  3. 3/5
  4. 3+5=8
  5. 1200x3/8=450
  6. 1200×5/8=750
Answered by alok05may2008
1

Step-by-step explanation:

given , Ahmed

p=8000

time=9months =3/4 years

Muneeb,

p=10000

time=12months=1years

putting together

some of interest of Ahmed and Muneeb

we all know that formule,

  • SI=p*r*t/100
  • some if interest of ahmed +muneeb
  • p*r*t/100 + p*r*t/100 =Rs.1200
  • 8000*r*3/4/100 + 10000*r*1/100=1200
  • r*60 + r*100 =1200
  • 60r+100r=1200
  • 160r=1200
  • r=15/2
  • for ahmed+ahmed
  • p*r*t/100 +p*r*t/100
  • 15/2(8000*3/4/100 + 10000*1/100)=1200

  • 1200=1200
  • so,ahmed lend interest=3/4 of 1200=900,1200-900=300
  • ahmed left one 1200-300=900
  • gets 300 as interset and muneeb gets900
  • as interest
  • ahmed amount=8000+300=8300
  • Muneeb amount=10000+900=10900
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