if ain theta is equal to 1 divided by 5 then the value of 1 by 5 cot square theta plus 1by 5 is
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if it is sin theta( which you have written ain)
there fore
let theta =x ( i am taking x in place of theta to write answer faster and it will take lot time to write theta everywhere )
so..
Sin x = 1/5. find 1/5 (cot)^2 + 1/5
ANS
cosec x = 5 (cosec x = 1/sin x)
( 1+(cot x)^2 =(cosec x) ^2
1+ (cot x)^2 =25
(cot x)^2 = 24 )
solving.... 1/5 cot x + 1/5
1/5 ×(24)+1/5
24/5+1/5
25/5
5 (ans)
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