If alfa and beeta are the Zeroes of the Polynomial 2x²+7x+5, write the value of alfa+beeta+alfa×beeta.
Answers
Answered by
0
Answer:
Step-by-step explanation:
Given: α and β are the zeros of polynomial 2x2 + 7x + 5 α + β = Sum of zeros = -(coefficient of x)/(coefficient of x2) = -7/2 αβ = Product of zeros = (constant term)/(coefficient of x2) = 5/2 α + β + αβ = (α + β) + αβ = -7/2 + 5/2 = -1
Similar questions