Question

if alfa and beeta are the zeroes of the polynomial p(x) = x2+2x-3 then find 1/alfa + 1/beeta​

Answer 1

Answer:

f(x)=x

2

−2x+3 have zeroes α,β

⇒α+β=2

⇒α⋅β=3

Now polynomial having α+2,β+2 as roots is

p(x)=x

2

−(α+2+β+2)x+(α+2)(β+2)

=x

2

−(α+β+4)x+αβ+2(α+β)+4

=x

2

−(2+4)x+3+2(2)+4

⇒x

2

−6x+11

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