if alfa and beta are the zeroes of the polynomial py = 5y^2-7y +1 find the value of 1 upon alfa plus 1 upon beta
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➡5y²-7y+1=0
We know that,
Sum of the zeroes= -b/a= -(-7)/5=7/5
Product of the zeroes=c/a=1/5
So,
7/5
1/5
Now,
↪1/alpha+1/beta
↪alpha+beta/alpha×beta
↪7/5/1/5
↪7=Answer
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