If alfa and beta are the zeroes of the polynomial x^2-5x+6 and find the value of 1/alfa^2+1/beta^2
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x^2-3x-2x+6=0
x(x-3)-2(x-3)=0
x-3=0
x=3
x-2=0
x=2
alpha=2
beta=3
1/5+1/10
3/10
x(x-3)-2(x-3)=0
x-3=0
x=3
x-2=0
x=2
alpha=2
beta=3
1/5+1/10
3/10
krishnapriya2003:
how did you get this
I am unable to understand
according to splitting the middle term method the
ooho yes absolutely
i splitted -5x as -2x -3x
thank you so much for your efforts
its ok
mark me as brainliest
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