if alfa and beta are the zeros of aquadratic polynomial p(x)=x²+2x+3, then the value of alfa beta will be
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Answered by
1
Answer:
Given that,
α,β are the zeroes of the polynomial p(x)=2x
2
−7x+3
Sum of zeroes (α+β)=
a
−b
=
2
−(−7)
=
2
7
Product of zeroes αβ=
a
c
=
2
3
∴α
2
+β
2
=(α+β)
2
−2αβ
=(
2
7
)
2
−2(
2
3
)
=
4
49
−
4
12
=
4
37
Step-by-step explanation:
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Answered by
2
Answer:
x2+3x+1x+3
=x(x+3) +1(x+3)
(x+1) (x+3)
x=-1 , x=-3
alpha =-1 and beta =-3
hope it's correct!!!!
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