If alfa and beta are the zeros of f(x)=x2-5x+k, such that alfa-beta=1, find k
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Answered by
1
alpha + beta =5
alpha - beta = 1
solving this...
2*alpha = 6
alpha = 3
so beta= 2
hence k= 3*2=6
alpha - beta = 1
solving this...
2*alpha = 6
alpha = 3
so beta= 2
hence k= 3*2=6
Answered by
6
F(x) = x2 - 5x + k
α- β = 1........i
Then using relation between zeros and co efficients,
α +β = 5..........ii
αβ = k.......iii
Solving i and ii
α + β = 5
α - β = 1
. .................
2α= 6
α= 3
Then β = 2
Substituting the values of α and β in iii
3*2 = K
Therefore k = 6
Hope this helps.... Plz mark as brainliest
α- β = 1........i
Then using relation between zeros and co efficients,
α +β = 5..........ii
αβ = k.......iii
Solving i and ii
α + β = 5
α - β = 1
. .................
2α= 6
α= 3
Then β = 2
Substituting the values of α and β in iii
3*2 = K
Therefore k = 6
Hope this helps.... Plz mark as brainliest
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