Question

if alfa and beta are the zeros of kx2-2x+3k such that alfa+beta=alfa×beta then k=?​

Answer 1

Answer:

hope this is correct and helps you..

Answer 2

The value of $k=\frac{2}{3}$.

Step-by-step explanation:

Given : If $\alpha$ and $\beta$ are the zeros of $kx^2-2x+3k$ such that $\alpha+\beta =\alpha \beta$.

To find : The value of k ?

Solution :

Quadratic equation $ax^2+bx+c=0$ with zeros $\alpha$ and $\beta$  are

$\alpha+\beta=-\frac{b}{a}$  and $\alpha \beta =\frac{c}{a}$

In equation $kx^2-2x+3k$, a=k, b=-2 and c=3k

Substitute the values,

$\alpha+\beta=-\frac{-2}{k}$  

$\alpha+\beta=\frac{2}{k}$  

and  $\alpha \beta =\frac{3k}{k}$

$\alpha \beta =3$

Substitute the values in $\alpha+\beta =\alpha \beta$

$\frac{2}{k} =3$

$k=\frac{2}{3}$

Therefore, the value of $k=\frac{2}{3}$.

#Learn more

If alfa and beta are the zeros of a polynomial x2-4root3x+3, then find the value of alfa+beta-alfa beta.

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