Question

if alfa and beta are zero of x^2 + 5x+8 , then the value of alfa + beta is​

Answer 1

Answer:

Alfa+beta= -5

Step-by-step explanation:

x²+5x+8=0

Alfa+beta = -b/a

a=1. b=5 c=8

Alfa+beta= -b/a

= -5/1

=-5

I hope it is helpful

Answer 2

Answer:

$\alpha + \beta = { - 5}$

Step-by-step explanation:

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In the standard form of quadratic equation (ax² + bx + c), here -

a = 1 [Coefficient of x²]

b = 5 [coefficient of x]

c = 8

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Question asked is sum of two zeroes (alpha + beta) will be -

$sum \: of \: two \: zeroes( \alpha + \beta ) = \frac{ - b}{a} \\ = \frac{ - (5)}{1} \\ = - 5$

Hence sum of two zeroes will be -5.

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More information -

If the two zeroes are alpha and beta, so

$\alpha + \beta = - \frac{ b}{a} \\ \alpha \beta = \frac{c}{a}$

Formula to find zeroes of quadratic equation =

$\frac{ - b ± \sqrt{ {b}^{2} - 4ac} }{2a}$

If the discriminant,

• b² - 4ac < 0, so zeroes are unreal and imaginary.
• b² - 4ac = 0, so zeroes are real and equal.
• b² - 4ac > 0, so zeroes are real and unequal.

Any quadratic equation have not more than two zeroes.

hope it helps.