Math, asked by snaitik324, 8 months ago

if alfa and bita are the two zeroes of quadratic polynomials p(x)=x^2-(k+6)x+2(2k-1),then find the value of k, if (alfa+bita)=(alfa into bita)/2

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Answered by FakeWorldBc

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Answered by lalitnit

Answer:

p(x)=x^2-(k+6)x+2(2k-1)

Given,

(alfa+bita)=(alfa into bita)/2

(k+6)+2(2k-1) = (k+6)*2*(2k-1)/2

(k+6)+4k-2= (k+6)*(2k-1)

5k+4= 2k^2 - k + 12k - 6

0 = 2k^2 + 6k - 10

k^2 + 3k - 5 = 0

On solving the quadratic equation

k = 4.1925

k = - 1.1925

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if alfa and bita are the two zeroes of quadratic polynomials p(x)=x^2-(k+6)x+2(2k-1),then find the value of k, if (alfa+bita)=(alfa into bita)/2​

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if alfa and bita are the two zeroes of quadratic polynomials p(x)=x^2-(k+6)x+2(2k-1),then find the value of k, if (alfa+bita)=(alfa into bita)/2